Operational research B.C.A 17-20 SEM 4, Sec Internal March 2019
SAINTGITS
COLLEGE OF APPLIED SCIENCES
SECOND INTERNAL ASSESSMENT EXAMINATION, March2019
Department of BCA, Semester 4
Operational Research
Total : 80 marks Time:3Hours
Section
A
1.Sum of supply not equal to sum of
demand
2.Solution which satisfies the
objective function.
3.Set of values of the variables which
satisfy all the constraints and non negative restrictions of the problem.
4.Min z=
,
, 



5.Number of allocation is less than
m+n-1
6.Position in the pay off matrix where
the maximin coincides with minimax
7.2
8.If the algebraic sum of the outcomes
of all players together is zero.
9.In L.P.P constraints are ≥ type we
add surplus variable to make equality.
10.Assign a number of persons to equal
number of destination at minimum cost.
11.Number of rows not equal to number
of columns. In this case we introduce dummy rows or columns.
12.In a L.P.P if there are m variables
and n constraints .If m>n , then we put zero values for m-n variables .
These n variables are called basic and m-n variables are called non basic
variables.
Section B
13.6
14.Draw graph x=.75, y=3.5 z=19.75
X=.8,y=3.6
z=20.4
X=4,
y=6 , z= 42
X=4,
y=2, z= 22
X=2, y=2, z=19 is the solution
15.A-I 6 units, B-I 1 unit
16. Transportation
Problem-Subclass of linear programming problem, Number of origins need not be
equal to number of destination. Unbalanced if sum of supply not equal to sum of
demand. Here a positive quantity is allocated from a source to destination.
Assignment problem
–Special type of transportation problem, Number of rows and columns are equal.
unbalanced if number of rows and columns are not equal. Here a job is assigned
to a destination.
17.first table key element 1, second table
key element-5, x=
,y=
, z=18


18.(1) There are finite number of
players(2)Each player has a finite number of course of action(3)Every play is
associated with an outcome known as pay off(4) A play is said to be played when each of the
players choose a single course of action.
19.After the initial basic feasible solution
form m=n-1 equations of the form ui+vj=cij
corresponding to each occupied cell. For solving the equations , take one of ui
or vj as zero. Calculate dij=cij-(ui+vij)If
all dij≥0, the solution is
optimal.
20.The principle of dominance states that if
the strategy of a player dominates over another in all conditions, then the
latter can be ignored.
21.111
(6x5=30)
Section C.
22.A-1,
B-2, c-3, D-4
A-1, B-3, C-2, D-4, cost=50
23.
First table key element=8-2M, second table key element=3-M, third table key
element—M+8, x=80, y=120, z=1200
24.
In a game ,if the algebraic sum of the outcomes of all the players together is
zero, the game is called zero sum game. Otherwise non zero sum game. Using
dominance principle solve the problem .
25.
Using vogel’s method find the initial basic solution and then solve.
Comments
Post a Comment