Basic Statistics and introductory probability theory, Semester 1(2020-23), First Internal Feb 2021

 

BASIC STATISTICS AND INTRODUCTORY PROBABILITY THEORY

Total : 50 marks                                                         Time: 2 hours

Section A

Answer any 5 questions. Each question carries 2 marks.

 

1. statistics should be an aggregate of facts, numerically expressed, collected in systematic manner, collected for predetermined purposes, simplify complexity

2. AM can be easily calculated; it can be determined in most of the cases.it is based on all observations of the data. Thus, mean satisfies many of the properties of a good average. That is why arithmetic mean is considered to be the best average.

3. Correlation is the relationship between two or more variables.

    Eg: Relation between demand and supply

4. Regression is the prediction of the unknown variable’s value from known variable’s value

5. probable error of the coefficient of correlation is a statistical measure which measures reliability and dependability of the value of coefficient of correlation

        Or P.E= 0.6745(1-r2)/sqrt(n)

6. 3x+2y+4=0

   3x= -2y-4

     x = -0.67y-1.33,   bxy=-0.67  or -2/3

    

Section B

Answer any 5 questions. Each question carries 5 marks.

7. n1 =22, n2= 18,

    Combined mean=22x15+18x20/22+18=17.25

8. properties of correlation coefficient-it has a well-defined formula, it is independent of the unit of measurement, it lies between -1 and 1, it does not change with reference to change of origin

Difference between correlation and regression-1) in correlation, we study degree of relationship between the variables.in regression analysis-we study the nature of relationship 2) in correlation analysis, the choice of dependent and independent variables is purely personal choice, in regression analysis, one has to decide which variable shall be taken as dependent and which as independent

3) correlation is not for prediction and regression is used for prediction

9.

X

5

8

7

11

9

10

8

2

4

6

X2

25

64

49

121

81

100

64

4

16

36

S.D=sqrt(560/10-(70/10)2=sqrt(56-49=sqrt(7)=2.646

10.r=0.2

   1-0.02=6∑ D2/n (n2-1)

  ∑D2 =792/6=132,  correct    ∑D2 =132-49+81=164

  There fore correct correlation coefficient=1-0.99=0.01

 

11.

x

y

xy

Y2

 5

4

20

16

6

5

30

25

7

8

56

64

3

2

6

4

2

1

2

1

23

20

114

110

bxy=0.73, mean of x=4.6, mean of y=4

 Regression equation of x on y is x-4.6=0.73(y-4)

X=0.73y+1.68

12.

x

1/x

f

f/x

60

0.016

600

10

15

0.0667

300

20

350

0.0029

700

2

50

0.0200

25

0.5

Average speed=N/∑ f(1/x)= 1625/32.5=50K.M p.h

Section C

Answer any 1 question. It carries 15 marks.

13. mean=33.71,median=33.5 and mode=33.85,and draw less than ogive by writing less than cumulative frequency

14. Karl Pearson’s correlation coefficient= 35770-37045/sqrt(24850-24025)*(53250-57121)     

     =-1275/1325.2=-0.962=negative correlation

byx =1.5,mean of x=4,mean of y=5.8,y=1.5x-0.2

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